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Question-186965




Question Number 186965 by 073 last updated on 12/Feb/23
Commented by 073 last updated on 12/Feb/23
solution please??
solutionplease??
Answered by Rasheed.Sindhi last updated on 12/Feb/23
(2△(−3))△(((−2)△(−1))  =(2^2 +(−3))△( (−2)−2(−1))  =1△0  =1^2 +0  =1
(2(3))(((2)(1))=(22+(3))((2)2(1))=10=12+0=1
Commented by 073 last updated on 14/Feb/23
nice solution  thanks alot
nicesolutionthanksalot

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