Question-187029

Question Number 187029 by yaslm last updated on 12/Feb/23

Answered by cortano12 last updated on 12/Feb/23

(1) \lim_{x \to - 2^{-}} (a x + b) = \lim_{x \to - 2^{+}} (x^{2} + 2 b - 17)

- 2 a + b = 4 + 2 b - 17

- 2 a - b = - 13

(2) \lim_{x \to 1^{-}} (x^{2} + 2 b - 17) = \lim_{x \to 1^{+}} (3 x - 3 + a)

1 + 2 b - 17 = 3 - 3 + a

- a + 2 b = 16 \Rightarrow a = 2 b - 16

\Rightarrow - 2 (2 b - 16) - b = - 13

\Rightarrow - 5 b = - 45 \Rightarrow {\begin{cases} b = 9 \\ a = 2 \end{cases}