Question Number 187051 by pascal889 last updated on 13/Feb/23
Commented by mr W last updated on 13/Feb/23
$$\left(\mathrm{1}+\frac{\mathrm{1}}{\mathrm{1000}}\right)^{\mathrm{8}} =\underset{{n}=\mathrm{0}} {\overset{\mathrm{8}} {\sum}}\frac{{C}_{{n}} ^{\mathrm{8}} }{\mathrm{10}^{\mathrm{3}{n}} } \\ $$