Question Number 187190 by 073 last updated on 14/Feb/23
Answered by aba last updated on 14/Feb/23
$$\mathrm{x}\Delta\mathrm{e}=\mathrm{x}\Rightarrow−\mathrm{3x}×\mathrm{e}−\mathrm{3x}−\mathrm{3e}−\mathrm{4}=\mathrm{x} \\ $$$$\Rightarrow−\mathrm{3e}\left(\mathrm{x}+\mathrm{1}\right)=\mathrm{4}\left(\mathrm{x}+\mathrm{1}\right)\Rightarrow\:\mathrm{e}=−\frac{\mathrm{4}}{\mathrm{3}} \\ $$
Commented by 073 last updated on 15/Feb/23
$$\mathrm{thanks} \\ $$
Answered by HeferH last updated on 14/Feb/23
$$\:{x}\:\bigtriangleup\:{y}\:=\:−\mathrm{3}{xy}\:−\mathrm{3}{x}\:−\mathrm{3}{y}\:−\:\mathrm{4} \\ $$$$\:{x}\:\bigtriangleup\:{e}\:=\:{x} \\ $$$$\:{x}\:=\:−\mathrm{3}{xe}−\mathrm{3}{x}−\mathrm{3}{e}−\mathrm{4} \\ $$$$\:\mathrm{4}{x}\:+\:\mathrm{4}\:=\:−\mathrm{3}{xe}\:−\:\mathrm{3}{e} \\ $$$$\:{e}\left(\mathrm{3}{x}\:+\:\mathrm{3}\right)\:=\:−\mathrm{4}\:−\mathrm{4}{x} \\ $$$$\:{e}\:=\:\frac{−\mathrm{4}−\mathrm{4}{x}}{\mathrm{3}{x}+\mathrm{3}} \\ $$$$\:=\:\frac{−\mathrm{4}\left(\mathrm{1}\:+\:{x}\right)}{\mathrm{3}\left(\mathrm{1}\:+\:{x}\right)}\:=\:−\frac{\mathrm{4}}{\mathrm{3}} \\ $$
Commented by 073 last updated on 15/Feb/23
$$\mathrm{thanks}\:\mathrm{alot} \\ $$