Question Number 187252 by Rupesh123 last updated on 15/Feb/23
Answered by ajfour last updated on 15/Feb/23
Commented by ajfour last updated on 15/Feb/23
$${e}^{\mathrm{2}} +{f}^{\mathrm{2}} −{b}^{\mathrm{2}} −{d}^{\mathrm{2}} \\ $$$$={h}^{\mathrm{2}} +\left({s}+{c}\right)^{\mathrm{3}} +{h}^{\mathrm{2}} +\left({t}+{c}\right)^{\mathrm{2}} \\ $$$$\:\:\:\:\:−\left({h}^{\mathrm{2}} +{t}^{\mathrm{2}} \right)−\left({h}^{\mathrm{2}} +{s}^{\mathrm{2}} \right) \\ $$$$\:\:\:=\mathrm{2}{c}^{\mathrm{2}} +\mathrm{2}{c}\left({s}+{t}\right) \\ $$$$\:\:\:=\mathrm{2}{c}^{\mathrm{2}} +\mathrm{2}{c}\left({a}−{c}\right) \\ $$$$\:\:\:=\mathrm{2}{ac} \\ $$$$\:\:\:\:\:\:\:\: \\ $$$$ \\ $$
Commented by Rupesh123 last updated on 15/Feb/23
Good job!