Menu Close

Question-187257




Question Number 187257 by ajfour last updated on 15/Feb/23
Commented by ajfour last updated on 15/Feb/23
(x^2 −1)x=c      Find x.
$$\left({x}^{\mathrm{2}} −\mathrm{1}\right){x}={c}\:\:\:\:\:\:{Find}\:{x}. \\ $$
Commented by ajfour last updated on 15/Feb/23
Any good idea (?) to go about this:  (p−2c)^2 (p^2 −2cp−6c)=27(p+c)
$${Any}\:{good}\:{idea}\:\left(?\right)\:{to}\:{go}\:{about}\:{this}: \\ $$$$\left({p}−\mathrm{2}{c}\right)^{\mathrm{2}} \left({p}^{\mathrm{2}} −\mathrm{2}{cp}−\mathrm{6}{c}\right)=\mathrm{27}\left({p}+{c}\right) \\ $$$$ \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *