Question Number 187257 by ajfour last updated on 15/Feb/23
Commented by ajfour last updated on 15/Feb/23
$$\left({x}^{\mathrm{2}} −\mathrm{1}\right){x}={c}\:\:\:\:\:\:{Find}\:{x}. \\ $$
Commented by ajfour last updated on 15/Feb/23
$${Any}\:{good}\:{idea}\:\left(?\right)\:{to}\:{go}\:{about}\:{this}: \\ $$$$\left({p}−\mathrm{2}{c}\right)^{\mathrm{2}} \left({p}^{\mathrm{2}} −\mathrm{2}{cp}−\mathrm{6}{c}\right)=\mathrm{27}\left({p}+{c}\right) \\ $$$$ \\ $$