Question Number 18747 by khamizan833@yahoo.com last updated on 29/Jul/17
Answered by Joel577 last updated on 29/Jul/17
$$\left(−\mathrm{2}^{−\mathrm{4}} \right)^{\frac{\mathrm{3}}{\mathrm{2}}} \:=\:\left(−\mathrm{2}\right)^{−\mathrm{6}} \:=\:\mathrm{0},\mathrm{015625} \\ $$
Commented by Joel577 last updated on 29/Jul/17
$$\mathrm{i}\:\mathrm{have}\:\mathrm{a}\:\mathrm{doubt}\:\mathrm{with}\:\mathrm{the}\:\mathrm{plus}/\mathrm{minus}\:\mathrm{sign} \\ $$
Answered by Joel577 last updated on 29/Jul/17
$${x}^{\frac{\mathrm{3}}{\mathrm{2}}} \:=\:\frac{\mathrm{4}}{\mathrm{3}} \\ $$$${x}\:=\:\left(\frac{\mathrm{4}}{\mathrm{3}}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} \:=\:\sqrt[{\mathrm{3}}]{\frac{\mathrm{16}}{\mathrm{9}}}\:=\:\mathrm{2}\sqrt[{\mathrm{3}}]{\frac{\mathrm{2}}{\mathrm{9}}}\:\:\approx\:\mathrm{1},\mathrm{21} \\ $$