Question Number 187473 by Rupesh123 last updated on 17/Feb/23
Answered by HeferH last updated on 17/Feb/23
Commented by HeferH last updated on 17/Feb/23
$$\:\sqrt{\left(\mathrm{5}\sqrt{\mathrm{2}}\right)^{\mathrm{2}} −\mathrm{1}}\:=\:\mathrm{7}\: \\ $$$$\mathrm{5}{a}\:+\:{b}\:=\:\mathrm{7} \\ $$$$\mathrm{5}{b}\:+\:{a}\:=\:\mathrm{5}\: \\ $$$$\:{a}\:=\:\frac{\mathrm{5}}{\mathrm{4}};\:{b}\:=\:\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\:\Rightarrow\:\frac{{x}\:+\:\mathrm{3}}{\mathrm{4}}\:=\:\frac{\mathrm{4}}{{x}\:−\:\mathrm{3}} \\ $$$$\:{x}\:=\:\mathrm{5}\: \\ $$$$\:\Rightarrow\:{A}_{\bigtriangleup} \:=\:\frac{\left({x}\:+\mathrm{1}\right)\left(\mathrm{7}+{x}\right)}{\mathrm{2}}\:=\frac{\mathrm{6}\centerdot\mathrm{12}}{\mathrm{2}}\:=\:\mathrm{36}{u}^{\mathrm{2}} \\ $$
Commented by Rupesh123 last updated on 18/Feb/23
Excellent!