Question Number 187585 by Mingma last updated on 19/Feb/23
Commented by Mingma last updated on 19/Feb/23
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Answered by HeferH last updated on 20/Feb/23
$${let}\:{x}\:{be}\:{the}\:{side}\:{of}\:{the}\:{square} \\ $$$${x}\:+\:\mathrm{2}\sqrt{\mathrm{2}}\:+\:\frac{{x}}{\mathrm{2}}\:=\:\mathrm{6}\sqrt{\mathrm{2}} \\ $$$$\:\frac{\mathrm{3}{x}}{\mathrm{2}}=\mathrm{4}\sqrt{\mathrm{2}}\: \\ $$$$\:{x}^{\mathrm{2}} \:=\:\left(\frac{\mathrm{8}\sqrt{\mathrm{2}}}{\mathrm{3}}\right)^{\mathrm{2}} \:=\:\frac{\mathrm{128}}{\mathrm{9}}{u}^{\mathrm{2}} \\ $$
Commented by Rupesh123 last updated on 22/Feb/23
Nice work!