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Question-187752




Question Number 187752 by Noorzai last updated on 21/Feb/23
Commented by Noorzai last updated on 21/Feb/23
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Commented by Noorzai last updated on 21/Feb/23
can you help me to answer
$${can}\:{you}\:{help}\:{me}\:{to}\:{answer} \\ $$
Commented by mr W last updated on 21/Feb/23
there are at least one million of such  similar questions. do you want to  post all of them? if you don′t want to  or are not able to learn from the   similar questions which other people  have solved for you, then it makes no   sense to solve this question for you,   because you will also not learn from   this one.
$${there}\:{are}\:{at}\:{least}\:{one}\:{million}\:{of}\:{such} \\ $$$${similar}\:{questions}.\:{do}\:{you}\:{want}\:{to} \\ $$$${post}\:{all}\:{of}\:{them}?\:{if}\:{you}\:{don}'{t}\:{want}\:{to} \\ $$$${or}\:{are}\:{not}\:{able}\:{to}\:{learn}\:{from}\:{the}\: \\ $$$${similar}\:{questions}\:{which}\:{other}\:{people} \\ $$$${have}\:{solved}\:{for}\:{you},\:{then}\:{it}\:{makes}\:{no}\: \\ $$$${sense}\:{to}\:{solve}\:{this}\:{question}\:{for}\:{you},\: \\ $$$${because}\:{you}\:{will}\:{also}\:{not}\:{learn}\:{from}\: \\ $$$${this}\:{one}. \\ $$
Commented by mr W last updated on 21/Feb/23
no, i won′t, because i don′t believe  that someone can understand   ∫^∞ _0 ((ln x)/(1−x^7 )) dx, but is not able to solve a  kindergarten question.
$${no},\:{i}\:{won}'{t},\:{because}\:{i}\:{don}'{t}\:{believe} \\ $$$${that}\:{someone}\:{can}\:{understand} \\ $$$$\:\underset{\mathrm{0}} {\int}^{\infty} \frac{\mathrm{ln}\:{x}}{\mathrm{1}−{x}^{\mathrm{7}} }\:{dx},\:{but}\:{is}\:{not}\:{able}\:{to}\:{solve}\:{a} \\ $$$${kindergarten}\:{question}. \\ $$
Commented by mahdipoor last updated on 21/Feb/23
get   ax+b=(6/7)+1(1/(11))+1(1/(13))      a,b=???  x=(4/7)+(5/(11))+(6/(13))⇒ax=((4a)/7)+((5a)/(11))+((6a)/(13))⇒  (ax+b)−(ax)=((6/7)+1(1/(11))+1(1/(13)))−(((4a)/7)+((5a)/(11))+((6a)/(13)))  ⇒b=((6−4a)/7)+((12−5a)/(11))+((14−6a)/(13))  guess value of a with option ⇒  a=2 or −2⇒   if a=2 ,b=((−2)/7)+...∉Z  ⇒a=−2 , b=((14)/7)+((22)/(11))+((26)/(13))=6  ⇒⇒−2x+6     with this method , you can answer problem  like this ...
$${get}\:\:\:{ax}+{b}=\frac{\mathrm{6}}{\mathrm{7}}+\mathrm{1}\frac{\mathrm{1}}{\mathrm{11}}+\mathrm{1}\frac{\mathrm{1}}{\mathrm{13}}\:\:\:\:\:\:{a},{b}=??? \\ $$$${x}=\frac{\mathrm{4}}{\mathrm{7}}+\frac{\mathrm{5}}{\mathrm{11}}+\frac{\mathrm{6}}{\mathrm{13}}\Rightarrow{ax}=\frac{\mathrm{4}{a}}{\mathrm{7}}+\frac{\mathrm{5}{a}}{\mathrm{11}}+\frac{\mathrm{6}{a}}{\mathrm{13}}\Rightarrow \\ $$$$\left({ax}+{b}\right)−\left({ax}\right)=\left(\frac{\mathrm{6}}{\mathrm{7}}+\mathrm{1}\frac{\mathrm{1}}{\mathrm{11}}+\mathrm{1}\frac{\mathrm{1}}{\mathrm{13}}\right)−\left(\frac{\mathrm{4}{a}}{\mathrm{7}}+\frac{\mathrm{5}{a}}{\mathrm{11}}+\frac{\mathrm{6}{a}}{\mathrm{13}}\right) \\ $$$$\Rightarrow{b}=\frac{\mathrm{6}−\mathrm{4}{a}}{\mathrm{7}}+\frac{\mathrm{12}−\mathrm{5}{a}}{\mathrm{11}}+\frac{\mathrm{14}−\mathrm{6}{a}}{\mathrm{13}} \\ $$$${guess}\:{value}\:{of}\:{a}\:{with}\:{option}\:\Rightarrow \\ $$$${a}=\mathrm{2}\:{or}\:−\mathrm{2}\Rightarrow\:\:\:{if}\:{a}=\mathrm{2}\:,{b}=\frac{−\mathrm{2}}{\mathrm{7}}+…\notin{Z} \\ $$$$\Rightarrow{a}=−\mathrm{2}\:,\:{b}=\frac{\mathrm{14}}{\mathrm{7}}+\frac{\mathrm{22}}{\mathrm{11}}+\frac{\mathrm{26}}{\mathrm{13}}=\mathrm{6} \\ $$$$\Rightarrow\Rightarrow−\mathrm{2}{x}+\mathrm{6}\:\:\: \\ $$$${with}\:{this}\:{method}\:,\:{you}\:{can}\:{answer}\:{problem} \\ $$$${like}\:{this}\:…\: \\ $$

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