Question-187819 Tinku Tara June 4, 2023 Geometry 0 Comments FacebookTweetPin Question Number 187819 by normans last updated on 22/Feb/23 Answered by mr W last updated on 22/Feb/23 Commented by mr W last updated on 22/Feb/23 a=10b=8cosα=2ca+bED2=a2+c2−2ac×2ca+bBD2=a2+4c2−4ac×2ca+bED2+BD2=c2a2+c2−2ac×2ca+b+a2+4c2−4ac×2ca+b=c2c2=a2(a+b)2(2a−b)⇒c=aa+b2(2a−b)BC=(a+b)2−(2c)2=b(a2−b2)2a−bareaoftriangleABC:Δ=(2c)×BC2=aa+b2(2a−b)b(a2−b2)2a−bΔ=a(a+b)2a−bb(a−b)2Δ=10×18128×22=302✓ Commented by normans last updated on 22/Feb/23 nicesolution,thankyousir Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: dy-dx-y-4y-3-3y-2-x-with-y-1-1-Next Next post: x-2-e-x-2-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.