Question Number 187830 by normans last updated on 22/Feb/23
Commented by normans last updated on 22/Feb/23
$$\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{find}}\:\boldsymbol{{r}}\:=??? \\ $$$$\: \\ $$
Answered by HeferH last updated on 22/Feb/23
$$\left({r}+\mathrm{12}\right)^{\mathrm{2}} \:=\:\left(\mathrm{24}−{r}\right)^{\mathrm{2}} \:+\:\mathrm{6}^{\mathrm{2}} \\ $$$$\:\left({r}+\mathrm{12}+\mathrm{24}−{r}\right)\left({r}+\mathrm{12}−\mathrm{24}+{r}\right)\:=\:\mathrm{36} \\ $$$$\:\mathrm{2}{r}\:−\mathrm{12}\:=\:\mathrm{1} \\ $$$$\:{r}\:=\:\frac{\mathrm{13}}{\mathrm{2}} \\ $$
Commented by normans last updated on 22/Feb/23
$$\:{nice} \\ $$