Question Number 188268 by normans last updated on 27/Feb/23
Commented by normans last updated on 27/Feb/23
$$\boldsymbol{{find}}\:\boldsymbol{{x}}\:=\:??? \\ $$
Commented by universe last updated on 27/Feb/23
$$\mathrm{1} \\ $$
Answered by manxsol last updated on 27/Feb/23
$$\frac{\left({b}_{\mathrm{1}} +{b}_{\mathrm{2}} \right){h}}{\mathrm{2}}=\mathrm{15}.\mathrm{75} \\ $$$${b}_{\mathrm{1}} +{b}_{\mathrm{2}} =\mathrm{6}.\mathrm{3} \\ $$$$\frac{{x}\sqrt{\mathrm{2}}}{\mathrm{2}}+\frac{\left({x}+\mathrm{6}\right)\sqrt{\mathrm{2}}}{\mathrm{2}}=\mathrm{6}.\mathrm{3} \\ $$$$\mathrm{2}{x}+\mathrm{6}=\mathrm{6}.\mathrm{3}\sqrt{\mathrm{2}} \\ $$$${x}=\frac{\mathrm{6}.\mathrm{3}\sqrt{\mathrm{2}}−\mathrm{6}}{\mathrm{2}} \\ $$$${x}=\mathrm{1}.\mathrm{45} \\ $$