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Question-188441




Question Number 188441 by 073 last updated on 01/Mar/23
Answered by cortano12 last updated on 01/Mar/23
P(x−2)=(x−2)^2 +4(x−2)+1  P(x−2)=x^2 −4x+4+4x−8+1  P(x−2)=x^2 −3   the constant is −3
$$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\left(\mathrm{x}−\mathrm{2}\right)^{\mathrm{2}} +\mathrm{4}\left(\mathrm{x}−\mathrm{2}\right)+\mathrm{1} \\ $$$$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{4x}+\mathrm{4}+\mathrm{4x}−\mathrm{8}+\mathrm{1} \\ $$$$\mathrm{P}\left(\mathrm{x}−\mathrm{2}\right)=\mathrm{x}^{\mathrm{2}} −\mathrm{3}\: \\ $$$$\mathrm{the}\:\mathrm{constant}\:\mathrm{is}\:−\mathrm{3}\: \\ $$

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