Question Number 188647 by Rupesh123 last updated on 04/Mar/23
Commented by mr W last updated on 05/Mar/23
$$\mathrm{4}. \\ $$$$\underset{{max}} {\mathrm{3}}^{\:\:\:\frac{\mathrm{1}}{\mathrm{3}}} >\mathrm{2}^{\frac{\mathrm{1}}{\mathrm{2}}} =\mathrm{4}^{\frac{\mathrm{1}}{\mathrm{4}}} >\mathrm{5}^{\frac{\mathrm{1}}{\mathrm{5}}} >\mathrm{6}^{\frac{\mathrm{1}}{\mathrm{6}}} >…>\underset{{min}} {\mathrm{1}} \\ $$