Question-189079

Question Number 189079 by pascal889 last updated on 11/Mar/23

Answered by HeferH last updated on 11/Mar/23

\sqrt[3]{\frac{1}{7^{3}}} + \sqrt[3]{\frac{1}{4^{3}}} - \frac{1}{\sqrt{\frac{4}{9}}} = \frac{1}{7} + \frac{1}{4} - \frac{1}{(\frac{2}{3})} = \frac{11}{28} - \frac{3}{2}

= - \frac{31}{28}

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