Question Number 189367 by 073 last updated on 15/Mar/23
Answered by HeferH last updated on 15/Mar/23
$$\:\Box\left(\left(\mathrm{a}+\mathrm{1}\right)^{\mathrm{2}} \right)=\mathrm{a} \\ $$$$\:\bigtriangleup\left(\mathrm{a}\right)\:=\:\frac{\mathrm{3a}}{\mathrm{2}} \\ $$$$\:\oplus\left(\frac{\mathrm{3a}}{\mathrm{2}}\right)\:=\:\mathrm{a}+\mathrm{7} \\ $$$$\:\bullet\:\bigtriangleup\left(\mathrm{18}\right)\:=\:\frac{\mathrm{3}\centerdot\mathrm{18}}{\mathrm{2}}\:=\:\mathrm{27} \\ $$$$\:\bullet\:\oplus\left(\mathrm{27}\right)\:=\:\mathrm{18}+\mathrm{7}\:=\:\mathrm{25} \\ $$$$\:\bullet\:\Box\left(\left(\mathrm{a}+\mathrm{1}\right)^{\mathrm{2}} \right)=\mathrm{a} \\ $$$$\:\left(\mathrm{a}+\mathrm{1}\right)^{\mathrm{2}} =\mathrm{25} \\ $$$$\:\mathrm{a}\:=\:\mathrm{4} \\ $$$$\:\bullet\:\Box\left(\left(\mathrm{4}+\mathrm{1}\right)^{\mathrm{2}} \right)=\:\mathrm{4} \\ $$$$\:\therefore\:\Box\left(\oplus\left(\bigtriangleup\left(\mathrm{18}\right)\right)\right)\:=\:\mathrm{4} \\ $$
Commented by 073 last updated on 15/Mar/23
$$\mathrm{nice}\:\mathrm{solution} \\ $$