Question Number 189409 by cherokeesay last updated on 15/Mar/23
Answered by HeferH last updated on 15/Mar/23
Commented by HeferH last updated on 15/Mar/23
$$\frac{\mathrm{y}}{\mathrm{4}}\:=\:\frac{\mathrm{6}}{\mathrm{21}} \\ $$$$\:\mathrm{y}\:=\:\frac{\mathrm{24}}{\mathrm{21}} \\ $$$$\mathrm{say}\:\mathrm{BE}\:=\:\mathrm{m}+\:\mathrm{n} \\ $$$$\:\frac{\mathrm{m}}{\mathrm{n}}\:=\:\frac{\mathrm{12}}{\mathrm{9}}\:=\:\frac{\mathrm{12k}}{\mathrm{9k}} \\ $$$$\:\mathrm{a}\:=\:\mathrm{21k} \\ $$$$\:\mathrm{n}\:=\:\mathrm{9k} \\ $$$$\:\frac{\mathrm{n}}{\mathrm{a}}\:=\:\frac{\mathrm{y}}{\mathrm{x}} \\ $$$$\:\frac{\mathrm{9}}{\mathrm{21}}\:=\:\frac{\mathrm{24}}{\mathrm{21x}} \\ $$$$\:\mathrm{x}\:=\:\frac{\mathrm{24}}{\mathrm{9}}\:=\:\frac{\mathrm{8}}{\mathrm{3}}\: \\ $$
Commented by cherokeesay last updated on 16/Mar/23
$${thank}\:{you}. \\ $$
Answered by mr W last updated on 16/Mar/23
$$\frac{\mathrm{15}−\mathrm{6}}{\mathrm{4}}=\frac{\mathrm{6}}{{x}} \\ $$$$\Rightarrow{x}=\frac{\mathrm{4}×\mathrm{6}}{\mathrm{9}}=\frac{\mathrm{8}}{\mathrm{3}} \\ $$
Commented by mr W last updated on 16/Mar/23
Commented by cherokeesay last updated on 16/Mar/23
$${Nice},\:{thank}\:{you}. \\ $$