Question Number 189506 by Rupesh123 last updated on 18/Mar/23
Answered by HeferH last updated on 18/Mar/23
Commented by HeferH last updated on 18/Mar/23
$$\mathrm{Area}\:=\:\mathrm{12}×\mathrm{14}\:−\:\left(\frac{\mathrm{12}×\mathrm{7}+\mathrm{7}×\mathrm{6}+\mathrm{14}×\mathrm{6}}{\mathrm{2}}\right) \\ $$$$\:=\:\mathrm{12}×\mathrm{14}\:−\frac{\mathrm{6}×\mathrm{7}\left(\mathrm{2}+\mathrm{1}+\mathrm{2}\right)}{\mathrm{2}}\: \\ $$$$\:=\:\mathrm{12}×\mathrm{14}\:−\:\mathrm{3}×\mathrm{7}×\mathrm{5}\:\:=\:\mathrm{168}\:−\:\mathrm{105}\:=\:\mathrm{63u}^{\mathrm{2}} \\ $$
Commented by Rupesh123 last updated on 18/Mar/23
Excellent!