Question Number 189664 by Rupesh123 last updated on 20/Mar/23
Answered by BaliramKumar last updated on 20/Mar/23
$${tan}\mathrm{5}°{tan}\left(\mathrm{60}°−\mathrm{5}°\right){tan}\left(\mathrm{60}°+\mathrm{5}°\right){tan}\mathrm{75}° \\ $$$${tan}\left(\mathrm{3}×\mathrm{5}°\right){tan}\mathrm{75}° \\ $$$${tan}\mathrm{15}°{tan}\mathrm{75}° \\ $$$${tan}\mathrm{15}°{cot}\mathrm{15}°\:=\:\mathrm{1} \\ $$