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Question-189899




Question Number 189899 by Mingma last updated on 23/Mar/23
Answered by HeferH last updated on 23/Mar/23
Commented by HeferH last updated on 24/Mar/23
(6−r)+(6(√3)−r)=12   6+6(√3)−12 = 2r   r = ((6(√3)−6)/2) = 3(√3)−3   (x/(3(√3)−3))= ((6(√3)−(3(√3)−3))/( (√((3(√3)−3)^2 +36))))   x = (((3(√3))^2 −9)/( (√(72−18(√3))))) = ((18)/( (√(8∙9−2∙9(√3)))))=((18)/(3(√(8−2(√3)))))   x = (6/( (√(8−2(√3))))) ≈ 2.81
(6r)+(63r)=126+6312=2rr=6362=333x333=63(333)(333)2+36x=(33)2972183=1889293=183823x=68232.81
Commented by Rupesh123 last updated on 24/Mar/23
Excellent!

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