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Question-189942

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Question Number 189942 by Rupesh123 last updated on 24/Mar/23
Answered by mr W last updated on 24/Mar/23
2R=a+2r+b ⇒R=((a+b)/2)+r (√((R−r)^2 −r^2 ))=R−r−b (√((((a+b)/2))^2 −r^2 ))=((a−b)/2) r^2 =(((a+b)/2))^2 −(((a−b)/2))^2 =ab ⇒r=(√(ab))
2R=a+2r+b⇒R=a+b2+r(R−r)2−r2=R−r−b(a+b2)2−r2=a−b2r2=(a+b2)2−(a−b2)2=ab⇒r=ab
Commented by Rupesh123 last updated on 24/Mar/23
Perfect ��
Commented by Skabetix last updated on 12/Apr/23
Commented by Skabetix last updated on 12/Apr/23
an other solution in french
anothersolutioninfrench

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