Question Number 189977 by cherokeesay last updated on 25/Mar/23
Answered by a.lgnaoui last updated on 26/Mar/23
$${the}\:\:{totale}\:{Area}: \\ $$$$\mathrm{2}\left(\mathrm{12}×\mathrm{3},\mathrm{5}+\mathrm{9}×\mathrm{3},\mathrm{5}\right)=\mathrm{147}{m}^{\mathrm{2}} \\ $$$${Area}\:{of}\:{windows}=\mathrm{21}{m}^{\mathrm{2}} \\ $$$${Area}\:{of}\:{tiles}=\mathrm{147}−\mathrm{21}=\mathrm{126}{m}^{\mathrm{2}} =\mathrm{126}×\mathrm{10}^{\mathrm{2}} {cm}^{\mathrm{2}} \\ $$$${Area}\:{of}\:{one}\:{tile}=\mathrm{225}{cm}^{\mathrm{2}} =\mathrm{15}×\mathrm{10}^{−\mathrm{2}} {m}^{\mathrm{2}} \\ $$$${Number}\:{of}\:{tiles}\:{necessary}\:\:{for}\:{the}\:{walls}: \\ $$$$=\frac{\mathrm{126}}{\mathrm{15}×\mathrm{10}^{−\mathrm{2}} }=\mathrm{840}\:\boldsymbol{{tiles}} \\ $$$$ \\ $$