Question Number 190230 by 073 last updated on 29/Mar/23
Answered by Rasheed.Sindhi last updated on 29/Mar/23
![a_5 =5−1=4 [ ∵ 5=2(2)+1 ] a_6 =2(6)+3=15 [ ∵ 6=2(3) ] a_5 +a_6 =4+15=19](https://www.tinkutara.com/question/Q190231.png)
$$\mathrm{a}_{\mathrm{5}} =\mathrm{5}−\mathrm{1}=\mathrm{4}\:\:\:\left[\:\because\:\:\mathrm{5}=\mathrm{2}\left(\mathrm{2}\right)+\mathrm{1}\:\right] \\ $$$$\mathrm{a}_{\mathrm{6}} =\mathrm{2}\left(\mathrm{6}\right)+\mathrm{3}=\mathrm{15}\:\:\:\left[\:\because\:\mathrm{6}=\mathrm{2}\left(\mathrm{3}\right)\:\right] \\ $$$$\mathrm{a}_{\mathrm{5}} +\mathrm{a}_{\mathrm{6}} =\mathrm{4}+\mathrm{15}=\mathrm{19} \\ $$
Answered by a.lgnaoui last updated on 29/Mar/23
$${n}=\mathrm{5}\:\Rightarrow\mathrm{5}\:{impair}\left(=\mathrm{2}×\mathrm{2}+\mathrm{1}\right) \\ $$$${a}_{\mathrm{5}} =\mathrm{5}−\mathrm{1}=\mathrm{4} \\ $$$${n}=\mathrm{6}\Rightarrow\mathrm{6}\:{pair}\left(\mathrm{6}=\mathrm{2}×\mathrm{3}\right) \\ $$$${a}_{\mathrm{6}} =\mathrm{2}×\mathrm{6}+\mathrm{3}=\mathrm{15} \\ $$$${alors}:\:\:\:{a}_{\mathrm{5}} +{a}_{\mathrm{6}} =\mathrm{15}+\mathrm{4} \\ $$$$\:\:\:\:\:\:\:\:\:\:\boldsymbol{{a}}_{\mathrm{5}} +\boldsymbol{{a}}_{\mathrm{6}} =\mathrm{19} \\ $$