Question Number 190565 by cherokeesay last updated on 06/Apr/23
Answered by mr W last updated on 06/Apr/23
$$\frac{{CB}}{\mathrm{sin}\:{x}}=\frac{{AC}}{\mathrm{sin}\:\mathrm{30}°}\:\:\:…\left({i}\right) \\ $$$$\frac{\mathrm{sin}\:\left({x}+\mathrm{30}°\right)}{{CB}}=\frac{\mathrm{sin}\:\left({x}+\mathrm{60}°\right)}{{DB}}\:\:\:…\left({ii}\right) \\ $$$$\left({i}\right)×\left({ii}\right): \\ $$$$\frac{\mathrm{sin}\:\left({x}+\mathrm{30}°\right)}{\mathrm{sin}\:{x}}=\frac{\mathrm{sin}\:\left({x}+\mathrm{60}°\right)}{\mathrm{sin}\:\mathrm{30}°} \\ $$$$\Rightarrow{x}=\mathrm{24}°\:{or}\:\mathrm{96}° \\ $$
Commented by mr W last updated on 06/Apr/23
Commented by mr W last updated on 06/Apr/23
