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Question-190760




Question Number 190760 by 073 last updated on 10/Apr/23
Answered by mehdee42 last updated on 10/Apr/23
(1/(2log_x 2))×(1/(log_x 3))=(1/(log_x 2))+(1/(2log_x 3))  ⇒lg_x 18=1⇒x=18
$$\frac{\mathrm{1}}{\mathrm{2}{log}_{{x}} \mathrm{2}}×\frac{\mathrm{1}}{{log}_{{x}} \mathrm{3}}=\frac{\mathrm{1}}{{log}_{{x}} \mathrm{2}}+\frac{\mathrm{1}}{\mathrm{2}{log}_{{x}} \mathrm{3}} \\ $$$$\Rightarrow{lg}_{{x}} \mathrm{18}=\mathrm{1}\Rightarrow{x}=\mathrm{18} \\ $$

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