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Question-190819




Question Number 190819 by Rupesh123 last updated on 12/Apr/23
Answered by HeferH last updated on 13/Apr/23
Commented by HeferH last updated on 13/Apr/23
A+B = 2A −2B  3B = A  ((PB)/(PA)) = ((4B)/(2B)) = (2/1)  ∴  ((AC)/(AP)) = (3/1) = 3
$$\mathrm{A}+\mathrm{B}\:=\:\mathrm{2A}\:−\mathrm{2B} \\ $$$$\mathrm{3B}\:=\:\mathrm{A} \\ $$$$\frac{\mathrm{PB}}{\mathrm{PA}}\:=\:\frac{\mathrm{4B}}{\mathrm{2B}}\:=\:\frac{\mathrm{2}}{\mathrm{1}} \\ $$$$\therefore\:\:\frac{\mathrm{AC}}{\mathrm{AP}}\:=\:\frac{\mathrm{3}}{\mathrm{1}}\:=\:\mathrm{3} \\ $$
Commented by Rupesh123 last updated on 14/Apr/23
Excellent, sir!

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