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Question-190845




Question Number 190845 by Rupesh123 last updated on 13/Apr/23
Answered by som(math1967) last updated on 13/Apr/23
Commented by som(math1967) last updated on 13/Apr/23
ar△ABC=(1/2)ADEB=(1/2)×10=5squ  ar△CBG=(1/2)CEFG=(1/2)×10=5squ  red area=△ABC+△CBG=10squnit
$${ar}\bigtriangleup{ABC}=\frac{\mathrm{1}}{\mathrm{2}}{ADEB}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{10}=\mathrm{5}{squ} \\ $$$${ar}\bigtriangleup{CBG}=\frac{\mathrm{1}}{\mathrm{2}}{CEFG}=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{10}=\mathrm{5}{squ} \\ $$$${red}\:{area}=\bigtriangleup{ABC}+\bigtriangleup{CBG}=\mathrm{10}{squnit} \\ $$

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