Question Number 190874 by Rupesh123 last updated on 13/Apr/23
Answered by cortano12 last updated on 13/Apr/23
$$\left(\mathrm{1}\right)\:\mathrm{26}^{\mathrm{2}} =\left(\mathrm{a}+\mathrm{t}\right)^{\mathrm{2}} +\mathrm{t}^{\mathrm{2}} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{20}^{\mathrm{2}} =\:\left(\mathrm{a}−\mathrm{t}\right)^{\mathrm{2}} +\mathrm{t}^{\mathrm{2}} \\ $$$$\:\Rightarrow\mathrm{46}.\mathrm{6}=\left(\mathrm{2a}\right)\left(\mathrm{2t}\right)\Rightarrow\mathrm{2at}=\mathrm{46}.\mathrm{3} \\ $$$$\Rightarrow\mathrm{area}\:\Delta\mathrm{ABC}\:=\:\frac{\mathrm{1}}{\mathrm{2}}.\mathrm{2a}.\mathrm{t}=\:\mathrm{23}×\mathrm{3}=\mathrm{69}\: \\ $$
Commented by Rupesh123 last updated on 13/Apr/23
Excellent, sir!