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Question-190878




Question Number 190878 by 073 last updated on 13/Apr/23
Answered by HeferH last updated on 13/Apr/23
(a/b) = (c/d) = (e/f)=k   a = bk   e = fk   c = dk   ((bfk^2 +d^2 k^2 )/(bf + d^2 )) = k^2 (((bf+d^2 )/(bf+d^2 ))) = k^2  × 1 = k^2
$$\frac{\mathrm{a}}{\mathrm{b}}\:=\:\frac{\mathrm{c}}{\mathrm{d}}\:=\:\frac{\mathrm{e}}{\mathrm{f}}=\mathrm{k} \\ $$$$\:\mathrm{a}\:=\:\mathrm{bk} \\ $$$$\:\mathrm{e}\:=\:\mathrm{fk} \\ $$$$\:\mathrm{c}\:=\:\mathrm{dk} \\ $$$$\:\frac{\mathrm{bfk}^{\mathrm{2}} +\mathrm{d}^{\mathrm{2}} \mathrm{k}^{\mathrm{2}} }{\mathrm{bf}\:+\:\mathrm{d}^{\mathrm{2}} }\:=\:\mathrm{k}^{\mathrm{2}} \left(\frac{\mathrm{bf}+\mathrm{d}^{\mathrm{2}} }{\mathrm{bf}+\mathrm{d}^{\mathrm{2}} }\right)\:=\:\mathrm{k}^{\mathrm{2}} \:×\:\mathrm{1}\:=\:\mathrm{k}^{\mathrm{2}} \\ $$
Commented by 073 last updated on 13/Apr/23
nice
$$\mathrm{nice} \\ $$

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