Question Number 190916 by Abdullahrussell last updated on 14/Apr/23
Commented by Rasheed.Sindhi last updated on 14/Apr/23
$$\mathrm{6}{A}+\mathrm{12}{B}+\mathrm{24}{C}=\mathrm{100} \\ $$$$\mathrm{6}\:\mid\:\left(\mathrm{6}{A}+\mathrm{12}{B}+\mathrm{24}{C}\right)\:\wedge\:\mathrm{6}\:\nmid\:\mathrm{100} \\ $$$$\Rightarrow\nexists\:{integer}\:{solution}! \\ $$