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Question-19095




Question Number 19095 by khamizan833@yahoo.com last updated on 04/Aug/17
Commented by ajfour last updated on 04/Aug/17
abc=18c−c^3  .
$$\mathrm{abc}=\mathrm{18c}−\mathrm{c}^{\mathrm{3}} \:. \\ $$
Commented by khamizan833@yahoo.com last updated on 05/Aug/17
show your work,please.
$$\mathrm{show}\:\mathrm{your}\:\mathrm{work},\mathrm{please}. \\ $$
Commented by ajfour last updated on 05/Aug/17
one more equation is needed  to determine c is what i mean  by my comment.
$$\mathrm{one}\:\mathrm{more}\:\mathrm{equation}\:\mathrm{is}\:\mathrm{needed} \\ $$$$\mathrm{to}\:\mathrm{determine}\:\mathrm{c}\:\mathrm{is}\:\mathrm{what}\:\mathrm{i}\:\mathrm{mean} \\ $$$$\mathrm{by}\:\mathrm{my}\:\mathrm{comment}. \\ $$

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