Question-191507

Question Number 191507 by Spillover last updated on 24/Apr/23

Answered by cortano12 last updated on 25/Apr/23

(a) \underset{- \infty}{\int^{\infty}} f (x) dx = 1

k \underset{0}{\int^{4}} (x^{2} - 3 x + 4) dx + \underset{4}{\int^{5}} 8 k dx = 1

k (\frac{64}{3} - \frac{3.16}{2} + 16) + 8 k (5 - 4) = 1

\frac{40 k}{3} + 8 k = 1 \Rightarrow k = \frac{3}{64}