Question Number 192203 by naka3546 last updated on 11/May/23
Answered by HeferH last updated on 11/May/23
$$\left(\mathrm{3h}−\mathrm{2x}\right)\mathrm{2h}\:=\:\mathrm{3hx} \\ $$$$\:\mathrm{6h}^{\mathrm{2}} −\mathrm{4hx}\:=\:\mathrm{3hx} \\ $$$$\:\mathrm{6h}^{\mathrm{2}} =\:\mathrm{7hx} \\ $$$$\:\mathrm{6h}\:=\:\mathrm{7x} \\ $$$$\:\frac{\mathrm{6h}}{\mathrm{7}}\:=\:\mathrm{x} \\ $$$$\:\frac{\mathrm{ON}}{\mathrm{NB}}\:=\:\frac{\mathrm{3h}−\frac{\mathrm{6h}}{\mathrm{7}}}{\mathrm{2h}+\frac{\mathrm{6h}}{\mathrm{7}}}\:=\:\frac{\frac{\mathrm{21h}−\mathrm{6h}}{\mathrm{7}}}{\frac{\mathrm{14h}+\mathrm{6h}}{\mathrm{7}}}\:=\:\frac{\mathrm{15h}}{\mathrm{7}}\centerdot\frac{\mathrm{7}}{\mathrm{20h}}\:=\:\frac{\mathrm{3}}{\mathrm{4}}\: \\ $$
Commented by HeferH last updated on 11/May/23
Commented by naka3546 last updated on 12/May/23
$$\mathrm{Thank}\:\:\mathrm{you} \\ $$