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Question-192543




Question Number 192543 by peter frank last updated on 20/May/23
Answered by leodera last updated on 20/May/23
Δ = ∫_0 ^(π/2) ((sin (x))/(sin (x)+cos (x)))dx  Δ = (1/2)∫_0 ^(π/2) ((sin (x)+cos (x))/(sin (x)+cos (x)))dx = (1/2)∫_0 ^(π/2) dx  Δ = (π/4)
Δ=0π2sin(x)sin(x)+cos(x)dxΔ=120π2sin(x)+cos(x)sin(x)+cos(x)dx=120π2dxΔ=π4

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