Question Number 20200 by ketto last updated on 24/Aug/17
Answered by Joel577 last updated on 24/Aug/17
![x . log 2 = 6x + 3 (x . log 2) − 6x = 3 x[(log 2) − 6] = 3 x = (3/((log 2) − 6))](https://www.tinkutara.com/question/Q20208.png)
$${x}\:.\:\mathrm{log}\:\mathrm{2}\:=\:\mathrm{6}{x}\:+\:\mathrm{3} \\ $$$$\left({x}\:.\:\mathrm{log}\:\mathrm{2}\right)\:−\:\mathrm{6}{x}\:=\:\mathrm{3} \\ $$$${x}\left[\left(\mathrm{log}\:\mathrm{2}\right)\:−\:\mathrm{6}\right]\:=\:\mathrm{3} \\ $$$${x}\:=\:\frac{\mathrm{3}}{\left(\mathrm{log}\:\mathrm{2}\right)\:−\:\mathrm{6}} \\ $$