Question Number 21124 by Joel577 last updated on 13/Sep/17
Answered by Tinkutara last updated on 13/Sep/17
$${Here}\:{w}\:{can}\:{be}\:{taken}\:{as}\:−{x}+{iy}. \\ $$$$\therefore−{iw}={i}\left({x}−{iy}\right)={y}+{ix},\:{which}\:{is}\:{in}\:\mathrm{1}^{{st}} \\ $$$${quadrant}.\:{Hence}\:{w}\:{will}\:{be}\:{A}. \\ $$
Commented by Joel577 last updated on 13/Sep/17
$${thank}\:{you}\:{very}\:{much} \\ $$
Answered by sma3l2996 last updated on 13/Sep/17
$${w}=\mid{w}\mid{e}^{{i}\theta} \\ $$$${so}\:\:−{iw}=\mid{w}\mid{e}^{{i}\theta+\frac{\mathrm{3}\pi}{\mathrm{2}}} ={A} \\ $$
Commented by Joel577 last updated on 14/Sep/17
$${thank}\:{you}\:{very}\:{much} \\ $$