Question Number 22475 by mondodotto@gmail.com last updated on 19/Oct/17
Commented by Rasheed.Sindhi last updated on 19/Oct/17
$$\left(\mathrm{b}\right)\mathrm{9}^{\mathrm{8x}^{\mathrm{2}} } \\ $$$$\sqrt{\mathrm{9}^{\mathrm{16x}^{\mathrm{2}} } }=\left(\mathrm{9}^{\mathrm{16x}^{\mathrm{2}} } \right)^{\mathrm{1}/\mathrm{2}} =\mathrm{9}^{\mathrm{16x}^{\mathrm{2}} ×\frac{\mathrm{1}}{\mathrm{2}}} \\ $$$$\:\:\:\:\:\:\:=\mathrm{9}^{\mathrm{8x}^{\mathrm{2}} } \\ $$