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Question-22941




Question Number 22941 by tawa tawa last updated on 24/Oct/17
Commented by tawa tawa last updated on 24/Oct/17
please help.
$$\mathrm{please}\:\mathrm{help}.\: \\ $$
Commented by ajfour last updated on 24/Oct/17
Commented by tawa tawa last updated on 24/Oct/17
I really appreciate sir. God bless you
$$\mathrm{I}\:\mathrm{really}\:\mathrm{appreciate}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you} \\ $$
Answered by ajfour last updated on 24/Oct/17
F_Y l=Mg(((2l)/5))  ⇒  F_Y =((2Mg)/5) =((2×40×10)/5) =160N  F_X l= Mg(((3l)/5)) =240N       ( 160N < 240N ) .
$${F}_{{Y}} {l}={Mg}\left(\frac{\mathrm{2}{l}}{\mathrm{5}}\right) \\ $$$$\Rightarrow\:\:{F}_{{Y}} =\frac{\mathrm{2}{Mg}}{\mathrm{5}}\:=\frac{\mathrm{2}×\mathrm{40}×\mathrm{10}}{\mathrm{5}}\:=\mathrm{160}{N} \\ $$$${F}_{{X}} {l}=\:{Mg}\left(\frac{\mathrm{3}{l}}{\mathrm{5}}\right)\:=\mathrm{240}{N}\: \\ $$$$\:\:\:\:\left(\:\mathrm{160}{N}\:<\:\mathrm{240}{N}\:\right)\:. \\ $$
Commented by tawa tawa last updated on 24/Oct/17
God bless you sir.  Any diagram ????
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$$$\mathrm{Any}\:\mathrm{diagram}\:???? \\ $$

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