Question Number 23408 by selestian last updated on 29/Oct/17
Answered by mrW1 last updated on 31/Oct/17
$$\mathrm{FE}=\frac{\mathrm{5}}{\mathrm{10}}×\mathrm{18}=\mathrm{9} \\ $$$$\mathrm{AC}=\frac{\mathrm{15}}{\mathrm{9}}×\left(\mathrm{5}+\mathrm{10}\right)=\mathrm{25} \\ $$$$\Rightarrow\mathrm{Answer}\:\left(\mathrm{b}\right) \\ $$