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Question-23679




Question Number 23679 by math solver last updated on 03/Nov/17
Answered by ajfour last updated on 03/Nov/17
(B) 2:3
$$\left({B}\right)\:\mathrm{2}:\mathrm{3} \\ $$
Commented by math solver last updated on 03/Nov/17
sir plzz provide sol. also....
$$\mathrm{sir}\:\mathrm{plzz}\:\mathrm{provide}\:\mathrm{sol}.\:\mathrm{also}…. \\ $$
Commented by math solver last updated on 04/Nov/17
??
$$?? \\ $$$$ \\ $$
Answered by mrW1 last updated on 04/Nov/17
∠BAC=∠BCA=15°  ∠OAC=60−15=45°  ∠OCA=45−15=30°  ∠OFA=∠OAC=45°  ∠OFC=180−45=135°  ∠COF=180−30−135=15°  ∠BOF=∠BOC−∠COF=45−15=30°  ((∠BOF)/(∠BOC))=((30)/(45))=(2/3)  ⇒answer (B)
$$\angle\mathrm{BAC}=\angle\mathrm{BCA}=\mathrm{15}° \\ $$$$\angle\mathrm{OAC}=\mathrm{60}−\mathrm{15}=\mathrm{45}° \\ $$$$\angle\mathrm{OCA}=\mathrm{45}−\mathrm{15}=\mathrm{30}° \\ $$$$\angle\mathrm{OFA}=\angle\mathrm{OAC}=\mathrm{45}° \\ $$$$\angle\mathrm{OFC}=\mathrm{180}−\mathrm{45}=\mathrm{135}° \\ $$$$\angle\mathrm{COF}=\mathrm{180}−\mathrm{30}−\mathrm{135}=\mathrm{15}° \\ $$$$\angle\mathrm{BOF}=\angle\mathrm{BOC}−\angle\mathrm{COF}=\mathrm{45}−\mathrm{15}=\mathrm{30}° \\ $$$$\frac{\angle\mathrm{BOF}}{\angle\mathrm{BOC}}=\frac{\mathrm{30}}{\mathrm{45}}=\frac{\mathrm{2}}{\mathrm{3}} \\ $$$$\Rightarrow\mathrm{answer}\:\left(\mathrm{B}\right) \\ $$

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