Question Number 25630 by tawa tawa last updated on 12/Dec/17
Answered by jota@ last updated on 13/Dec/17
$${m}_{{B}} {g}−{T}={m}_{{B}} {a} \\ $$$${T}={m}_{{A}} {a}.\:{Then} \\ $$$${m}_{{B}} {g}=\left({m}_{{A}} +{m}_{{B}} \right){a} \\ $$$${v}_{{A}} ^{\mathrm{2}} ={v}_{{B}} ^{\mathrm{2}} =\mathrm{2}{ah}\:\:\:\:\:\:\:{Because}\:{a}_{{A}} =\mathrm{0} \\ $$$${for}\:{displacement}\:{of}\:{m}_{{A}} \:>{h}.\: \\ $$$$\:{h}=\frac{{v}_{{A}} ^{\mathrm{2}} }{\mathrm{2}{a}}=\frac{{v}_{{A}} ^{\mathrm{2}} \left({m}_{{A}} +{m}_{{B}} \right)}{\mathrm{2}{m}_{{B}} {g}}. \\ $$
Commented by tawa tawa last updated on 13/Dec/17
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}.\:\mathrm{please}\:\mathrm{that}\:\mathrm{is}\:\mathrm{the}\:\mathrm{complete}\:\mathrm{question} \\ $$
Commented by tawa tawa last updated on 13/Dec/17
