Question-25738

Question Number 25738 by yesaditya22@gmail.com last updated on 13/Dec/17

Answered by mrW1 last updated on 13/Dec/17

\frac{a + b}{\sqrt{a b}} = 6

\frac{\frac{a}{b} + 1}{\sqrt{\frac{a}{b}}} = 6

l e t t^{2} = \frac{a}{b} ⩾ 0

\frac{t^{2} + 1}{t} = 6

t^{2} - 6 t + 1 = 0

t = \frac{6 \pm \sqrt{36 - 4}}{2} = 3 \pm 2 \sqrt{2}

\Rightarrow \frac{a}{b} = t^{2} = 6 t - 1 = 18 \pm 12 \sqrt{2} - 1 = 17 \pm 12 \sqrt{2}

Commented by Rasheed.Sindhi last updated on 14/Dec/17

Nice Sir!