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Question-25770




Question Number 25770 by tawa tawa last updated on 14/Dec/17
Answered by jota@ last updated on 15/Dec/17
2y+x=16  linea AC  A(16, 0) and C(0, 8)  y−2x=−2 linea BX   solving X(6, 5)  D= X+[X−(2, 2)]      = X+(4, 3 )=(10, 8)
$$\mathrm{2}{y}+{x}=\mathrm{16}\:\:{linea}\:{AC} \\ $$$${A}\left(\mathrm{16},\:\mathrm{0}\right)\:{and}\:{C}\left(\mathrm{0},\:\mathrm{8}\right) \\ $$$${y}−\mathrm{2}{x}=−\mathrm{2}\:{linea}\:{BX} \\ $$$$\:{solving}\:{X}\left(\mathrm{6},\:\mathrm{5}\right) \\ $$$${D}=\:{X}+\left[{X}−\left(\mathrm{2},\:\mathrm{2}\right)\right] \\ $$$$\:\:\:\:=\:{X}+\left(\mathrm{4},\:\mathrm{3}\:\right)=\left(\mathrm{10},\:\mathrm{8}\right) \\ $$$$ \\ $$$$ \\ $$

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