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Question-25868




Question Number 25868 by ajfour last updated on 16/Dec/17
Commented by ajfour last updated on 16/Dec/17
Find the area enclosed by a  variable line (x/t)+(y/(l−t))=1 and  the coordinate axes in the  first quadrant;   (the line shifts as t changes  from t=0 to t=l ).
$${Find}\:{the}\:{area}\:{enclosed}\:{by}\:{a} \\ $$$${variable}\:{line}\:\frac{{x}}{{t}}+\frac{{y}}{{l}−{t}}=\mathrm{1}\:{and} \\ $$$${the}\:{coordinate}\:{axes}\:{in}\:{the} \\ $$$${first}\:{quadrant};\: \\ $$$$\left({the}\:{line}\:{shifts}\:{as}\:{t}\:{changes}\right. \\ $$$$\left.{from}\:{t}=\mathrm{0}\:{to}\:{t}={l}\:\right). \\ $$
Commented by jota@ last updated on 16/Dec/17
  y_(max)  for x=a  (a/t)+(y/(l−t))=1             y=(1−a/t)(l−t)     ...(1)  y′=((a/t^2 ))(l−t)−(1−(a/t))  y′=0  a(l−t)−t(t−a)=0  t^2 −al=0    t=(√(al))    ...(2)  (2) into (1)  y=(1−(a/( (√(al)))))(l−(√(al)))  y=l−(√(al))−(√(al))+a       but  a=x  y=l−2(√(xl))+x  Area=∫_0 ^(l ) ydx=l^2 −((4l^2 )/3)+(l^2 /2)=(l^2 /6).
$$ \\ $$$${y}_{{max}} \:{for}\:{x}={a} \\ $$$$\frac{{a}}{{t}}+\frac{{y}}{{l}−{t}}=\mathrm{1}\:\:\:\:\:\:\:\:\:\:\: \\ $$$${y}=\left(\mathrm{1}−{a}/{t}\right)\left({l}−{t}\right)\:\:\:\:\:…\left(\mathrm{1}\right) \\ $$$${y}'=\left(\frac{{a}}{{t}^{\mathrm{2}} }\right)\left({l}−{t}\right)−\left(\mathrm{1}−\frac{{a}}{{t}}\right) \\ $$$${y}'=\mathrm{0} \\ $$$${a}\left({l}−{t}\right)−{t}\left({t}−{a}\right)=\mathrm{0} \\ $$$${t}^{\mathrm{2}} −{al}=\mathrm{0}\:\:\:\:{t}=\sqrt{{al}}\:\:\:\:…\left(\mathrm{2}\right) \\ $$$$\left(\mathrm{2}\right)\:{into}\:\left(\mathrm{1}\right) \\ $$$${y}=\left(\mathrm{1}−\frac{{a}}{\:\sqrt{{al}}}\right)\left({l}−\sqrt{{al}}\right) \\ $$$${y}={l}−\sqrt{{al}}−\sqrt{{al}}+{a}\:\:\:\:\:\:\:{but}\:\:{a}={x} \\ $$$${y}={l}−\mathrm{2}\sqrt{{xl}}+{x} \\ $$$${Area}=\int_{\mathrm{0}} ^{{l}\:} {ydx}={l}^{\mathrm{2}} −\frac{\mathrm{4}{l}^{\mathrm{2}} }{\mathrm{3}}+\frac{{l}^{\mathrm{2}} }{\mathrm{2}}=\frac{{l}^{\mathrm{2}} }{\mathrm{6}}. \\ $$
Commented by ajfour last updated on 09/Nov/24
beyond all praise! thanks. (repost)
$${beyond}\:{all}\:{praise}!\:{thanks}.\:\left({repost}\right) \\ $$

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