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Question-26200




Question Number 26200 by mubeen897@hotmail.com last updated on 22/Dec/17
Answered by ajfour last updated on 22/Dec/17
(0.2×10)+10+(0.2×20)−30+         0.5R+(0.5×10)=0  ⇒ 2+10+4−30+0.5R+[×]+5=0  or     0.5R = 9   ⇒   R=18Ω .
(0.2×10)+10+(0.2×20)30+0.5R+(0.5×10)=02+10+430+0.5R+[×]+5=0or0.5R=9R=18Ω.
Commented by mubeen897@hotmail.com last updated on 22/Dec/17
Sorry Bro answer is 18 Ohms I really tried to but its trickyy
SorryBroansweris18OhmsIreallytriedtobutitstrickyy
Commented by mubeen897@hotmail.com last updated on 22/Dec/17
But Nice Tryy
ButNiceTryy

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