Menu Close

Question-26354




Question Number 26354 by Tinkutara last updated on 24/Dec/17
Answered by ajfour last updated on 24/Dec/17
K=(1/2)mv^2   (dK/dx) =((mvdv)/dx)=ma  a=(1/m)((dK/dx))    hence (4) is correct.
$${K}=\frac{\mathrm{1}}{\mathrm{2}}{mv}^{\mathrm{2}} \\ $$$$\frac{{dK}}{{dx}}\:=\frac{{mvdv}}{{dx}}={ma} \\ $$$${a}=\frac{\mathrm{1}}{{m}}\left(\frac{{dK}}{{dx}}\right)\:\:\:\:{hence}\:\left(\mathrm{4}\right)\:{is}\:{correct}. \\ $$
Commented by Tinkutara last updated on 24/Dec/17
Thank you Sir!
$$\mathrm{Thank}\:\mathrm{you}\:\mathrm{Sir}! \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *