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Question-27959




Question Number 27959 by ajfour last updated on 17/Jan/18
Commented by ajfour last updated on 17/Jan/18
Inspired with Q.#27942
You can't use 'macro parameter character #' in math mode
Commented by beh.i83417@gmail.com last updated on 17/Jan/18
(r/(a/2))=((Ax)/(xC))⇒((2r)/a)=((Ax)/(xC))⇒((2r+a)/a)=(b/(Cx))  cosC=((a/2)/(xC))⇒xC=(a/(2cosC))  ⇒2r/a+1=(b/(a/(2cosC)))=((2bcosC)/a)⇒  2r+a=2bcosC⇒r=(1/2)(2bcosC−a)  1)a^2 =b^2 +c^2 −bc  2)cosC=((a^2 +b^2 −c^2 )/(2bc))=((b^2 +c^2 −bc+b^2 −c^2 )/(2bc))=  =((2b^2 −bc)/(2bc))  ⇒r=(1/2)(2b.((2b^2 −bc)/(2bc))−a)=((2b^2 −bc−ac)/(2c))  ⇒r=(b^2 /c)−((a+b)/2) .■
ra/2=AxxC2ra=AxxC2r+aa=bCxcosC=a/2xCxC=a2cosC2r/a+1=ba2cosC=2bcosCa2r+a=2bcosCr=12(2bcosCa)1)a2=b2+c2bc2)cosC=a2+b2c22bc=b2+c2bc+b2c22bc==2b2bc2bcr=12(2b.2b2bc2bca)=2b2bcac2cr=b2ca+b2.◼
Commented by ajfour last updated on 17/Jan/18
Sir, what does Ax, xC, ..mean ?
Sir,whatdoesAx,xC,..mean?
Commented by beh.i83417@gmail.com last updated on 17/Jan/18
x, is the intersection of AC with   perpendicular line drawn from midpoint  of BC.
x,istheintersectionofACwithperpendicularlinedrawnfrommidpointofBC.
Commented by beh.i83417@gmail.com last updated on 18/Jan/18
sir Ajfour! what about Q#27942 ?
You can't use 'macro parameter character #' in math mode
Commented by ajfour last updated on 18/Jan/18
thank you sir.
thankyousir.

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