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Question-28547




Question Number 28547 by tawa tawa last updated on 26/Jan/18
Answered by mrW2 last updated on 26/Jan/18
Area of ΔPQR=(1/2)×QR×PM=(1/2)×PR×QT  ⇒QR×PM=PR×QT  ⇒8×PM=7×4  ⇒PM=((7×4)/8)=(7/2)=3.5 cm
$${Area}\:{of}\:\Delta{PQR}=\frac{\mathrm{1}}{\mathrm{2}}×{QR}×{PM}=\frac{\mathrm{1}}{\mathrm{2}}×{PR}×{QT} \\ $$$$\Rightarrow{QR}×{PM}={PR}×{QT} \\ $$$$\Rightarrow\mathrm{8}×{PM}=\mathrm{7}×\mathrm{4} \\ $$$$\Rightarrow{PM}=\frac{\mathrm{7}×\mathrm{4}}{\mathrm{8}}=\frac{\mathrm{7}}{\mathrm{2}}=\mathrm{3}.\mathrm{5}\:{cm} \\ $$
Commented by tawa tawa last updated on 27/Jan/18
God bless you sir
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$

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