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Question-28921




Question Number 28921 by 803jaideep@gmail.com last updated on 01/Feb/18
Answered by Joel578 last updated on 01/Feb/18
10cos (200t) = 8  cos (200t) = 0.8  200t = cos^(−1) (0.8) ≈ 37°
$$\mathrm{10cos}\:\left(\mathrm{200}{t}\right)\:=\:\mathrm{8} \\ $$$$\mathrm{cos}\:\left(\mathrm{200}{t}\right)\:=\:\mathrm{0}.\mathrm{8} \\ $$$$\mathrm{200}{t}\:=\:\mathrm{cos}^{−\mathrm{1}} \left(\mathrm{0}.\mathrm{8}\right)\:\approx\:\mathrm{37}° \\ $$

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